a ball is thrown up at an angle of 30 degree with the harizontal if R and H represent in harizontal range and maximum height reaches then
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Maximum height, H = 2gu 2sin 2θ-----(i)
Horizontal range, R = gu 2 sin2θ
= g2u 2 ssinθcosθ------(ii)
Divide (i) by (ii), we get
RH
= 4tanθ
or tanθ=4H/R or θ=tan −1
(4H/R)
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