Math, asked by sumithrathiruvengada, 8 months ago

A ball is thrown up from the ground. It goes up 67 feet and comes down and falls into a dry well which is 23 feet deep. What is the distance travelled by the ball from the topmost point to the bottom of the well

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Answered by djain1315
2

Answer:

45 min

Step-by-step explanation:

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Physics

Motion in a Straight Line

Free Fall

A ball thrown up is caught ...

PHYSICS

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Asked on December 26, 2019 by

Barsha Sambyal

A ball thrown up is caught by the thrower 6 s after start. The height to which the ball has risen is (g=10m/s

2

).

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ANSWER

We know, v=u−gt−−−−(1)

(For a body thrown against gravity)

The ball returns the same position after 6s of throwing.

Ascending time= descending time

t, for moving maximum height is 3s.

At maximum height, v=0

So, (1)=> 0= u-gt

=u- 10×3

u= 30 m/s

Now, s= ut-

2

1

gt

2

s= (30×3)- 0.5×10×3

2

90-45

= 45m

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