A ball is thrown up from the ground with 50 m/s. While coming down it is caught at
height of 80 meters. What will be time of flight for the ball ?
(a) 5 sec
(b) 7 sec
(c) 10 sec
(d) 8 Sec
Answers
Answered by
10
Answer:
Answer is C.
The equation is given as v
2
−u
2
=2as.
where,
v = final velocity,
u = initial velocity,
a = acceleration due to gravity, 10m/s
2
,
s = h = height traveled.
Therefore, we can find u with above info. In this case, v = 0 at the top of the path.
0−u
2
=2×10×5=10m/s.
Hence, the initial velocity of the ball was 10 m/s.
Explanation:
Similar questions