Question

A ball is thrown up from the ground with a speed of 20 m/s. From the top of the building of
height 68 m, a second ball is simultaneously thrown down with a speed of 14 m/s. How long
do they take to meet?

Answer 1

Answer:

The distance covered is given as

s

1

=20t+5t

2

s

2

=30t−5t

2

s

1

+s

2

=150⇒150=50t⇒t=3s

Hence, the time after which both the balls will meet is 3 s.