Question

A ball is thrown up from the ground with a velocity of 30 m/s. It has a downward acceleration of 10 m/s2. At what height from the ground is the ball after 4 seconds?

Answer 1

Answer:

x=vt+1/2at^2

so,

x=30×4+1/2×10×4^2

=120+80

= 200 m

hope my answer is right!!