Question

A ball is thrown up from the top of a tower with 20 m\s velocity. It took the ball 6 seconds to fall to the bottom. For how long was the ball above the tower?

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Answer 1

Answer:

Explanation:

The initial velocity of the ball is =20 m/s.

The final velocity of the ball is =80 m/s.

The acceleration due to gravity is =10 m/s  

2

.

So, the height of the tower can be obtained from the expression:

v  

2

=u  

2

+2gh

Substitute the values in above expression:

80  

2

=20  

2

+(2×10×h)

h=  

20

6400−400

​

 m

h=  

20

6000

​

⇒300 m