A ball is thrown up from the top of the tower 50 m high from the velocity of 15 m/s . The time it takes to strike the ground is _____seconds . (Assume g = 10 m/sec².
a) 10s
b)3s
c) 5s
d) 2s
Answers
Answered by
7
S = ut + 1/2 at^2
-50=15t - 5t^2
t^2-3t-10=0
t=5,-2
t can no t be negative
So t=5 s
-50=15t - 5t^2
t^2-3t-10=0
t=5,-2
t can no t be negative
So t=5 s
Answered by
4
Answer:
5s
Explanation:
S = ut + 1/2 at^2
-50=15t - 5t^2
t^2-3t-10=0
t=5,-2
t can no t be negative
So t=5 s
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