Question

a ball is thrown up in vacuum returns after 12 s. its position after five seconds will be same as after?

Answer 1

Answer:

7 Seconds

Explanation:

Total time of Flight = 12s

Therefore time to reach the max height = 6s (i.e half of total t)

Now the position of the particle is same at time (t/2 + n) and (t/2 - n)

where n is any real no.

therefore, position at 6-1 seconds and 6+1 seconds is same

Hence answer is 7 seconds