A ball is thrown up the sum of kinetics and potentual energy will maximum at
Answers
Answer:
Kinetic Energy is given by:
KE = 1/2 × m × v × v
And Potential Energy is given by:
PE = m × g × h
Where m is mass of the object, v is its velocity, g is acceleration due to gravity and h is height.
Thus mass being unchanging and g approximated to 9.8, the point where h = 0.051 × v × v will be where kinetic energy is equal to potential energy. This value is obtained by equating KE to PE and solving for ‘h’.
In words it translates to: while launching an object of mass ‘m’ at velocity ‘v’, at a height of ‘0.051 × v × v’ the KE will be equal to the PE.
This is an ideal solution though. The hindrance being deceleration due to air resistance and gravity causing a reduction in the actual height where KE equals PE.
Explanation:
As you can see, when a ball is thrown at an angle, it never reaches a point where its kinetic energy is 0. However, some of its kinetic energy does become potential energy, and potential energy is at a maximum when the ball reaches its highest point.
Now in a projectile motion, it is the vertical velocity component that varies at a rate of “g”. The horizontal velocity component remains constant. Therefore, at the peak, since the V(y) = zero, the only KE is the horizontal: 23.5 J.The Potential Energy of the object at a height of 1m above the ground is given in a similar fashion. By definition, the change in Potential Energy is equivalent to the change in Kinetic Energy. The initial KE of the object is 0, because it is at rest. Hence the final Kinetic Energy is equal to the change in KE
Total energy at the time of projection
=
2
1
mv
2
=
2
1
×0.1(20)
2
=20J
Half way up, P.E. becomes half the P.E. at the top i.e.
P.E.=
2
20
=10J ∴K.E.=20−10=10J.
Kinetic Energy is given by:
KE = 1/2 × m × v × v
And Potential Energy is given by:
PE = m × g × h
Where m is mass of the object, v is its velocity, g is acceleration due to gravity and h is height.
Thus mass being unchanging and g approximated to 9.8, the point where h = 0.051 × v × v will be where kinetic energy is equal to potential energy. This value is obtained by equating KE to PE and solving for ‘h’.
In words it translates to: while launching an object of mass ‘m’ at velocity ‘v’, at a height of ‘0.051 × v × v’ the KE will be equal to the PE.
This is an ideal solution though. The hindrance being deceleration due to air resistance and gravity causing a reduction in the actual height where KE equals PE.
