A ball is thrown up under gravity (g=10m/s2). find it's velocity after 1 sec at height of 10m
Answers
Answered by
2
Answer:
5m/s
Explanation:
Given,
g= 10m/s^2, t = 1sec, h = 10m, u=?
Now using Equations of Motion,
h = ut + 1/2 g t ^2
10 = u + 1/2 x 10
u = 10 - 5
u = 5m/s
Answered by
0
Explanation:
Given,
g=10m/s²
t=1s
s=10m
and, v=0m/s
To find:- u=?
Now, we have the formula
s=ut+(1/2)gt²
Substituting the value, we get,
10=u*1+(1/2)*10*1*1
10=u+(1/2)10
10=u+5
u=5m/s
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