Question

A ball is thrown up under gravity (g=10m/s2). find it's velocity after 1 sec at height of 10m​

Answer 1

Answer:

5m/s

Explanation:

Given,

g= 10m/s^2, t = 1sec, h = 10m, u=?

Now using Equations of Motion,

h = ut + 1/2 g t ^2

10 = u + 1/2 x 10

u = 10 - 5

u = 5m/s

Answer 2

Explanation:

Given,

g=10m/s²

t=1s

s=10m

and, v=0m/s

To find:- u=?

Now, we have the formula

s=ut+(1/2)gt²

Substituting the value, we get,

10=u*1+(1/2)*10*1*1

10=u+(1/2)10

10=u+5

u=5m/s

Hope you may get it

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