Question

a ball is thrown up vertically at 15m/s. It is 2kg. what is its kinetic energy and how high will it go?

Answer 1

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A ball is thrown up with a speed of 15m/s. How high will it go before it begins to fall? Use g=9.8m/s².

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Kshitij Kumar Ummat

Answered Sep 1, 2017

Final speed at the top most point (v) = 0

Initial speed (u) = 15 m/s

a = -g = -9.8

Hence, as per the third law of motion,/

v square = u square + 2.a.s

or distance s = (v square - u square)/2.a

or s = (0 - 225)/(2 x -9.8)

or s = 225/19.6 = 11.48 mtrs Answer

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