Question

A ball is thrown up vertically returns back to the thrower after 6seconds.
What is the velocity with which it was thrown up

Answer 1

T=2u/g
6=2u/10
u=30m/s

Answer 2

_/\_Hello mate__here is your answer--

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The ball takes a total of 6 s for its upward and downward journey. (Time of ascent is equal to the time of descent.)

Hence, it has taken 3 s to reach at the maximum height.

v = 0 m/s

g = −9.8 ms−2

Using equation of motion,

v = u + at

⇒0 = u + (−9.8 × 3)

⇒ u = 9.8 × 3 = 29.4 m/s

Hence, the ball was thrown upwards with a velocity of 29.4 m/s.

I hope, this will help you.☺

Thank you______❤

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