Question

a ball is thrown up vertically returns to the thrower after 4s find the maximum height it reaches and it's position after 3s​

Answer 1

Here, t = 4s. In 3 s, the ball reaches the maximum height and in 1 s it falls from the top. Therefore, The ball will be 4.9 m below the top of the tower after 4 s.

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Answer 2

Answer:

Here, t = 4s. In 3 s, the ball reaches the maximum height and in 1 s it falls from the top. Therefore, The ball will be 4.9 m below the top of the tower after 4 s.