Question

A ball is thrown up vertically returns to the thrower after 6 seconds. find the velocity with which it was thrown up

Answer 1

Consider,

upward gravity = -9.8 m/s2

Total time (to and fro)= 6 s, so, upward journey = 6/2 = 3 s

Initial velocity (u) = ?

Final velocity (v) = 0 m/s

From First equation of motion,

Final velocity = Initial velocity +gt

or, 0 = u + (-9.8 X3)

or, u = 29.4 m/s

So, The velocity at which ball is thrown in the upward direction is 29.4 m/s.

Answer 2

_/\_Hello mate__here is your answer--

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The ball takes a total of 6 s for its upward and downward journey. (Time of ascent is equal to the time of descent.)

Hence, it has taken 3 s to reach at the maximum height.

v = 0 m/s

g = −9.8 ms−2

Using equation of motion,

v = u + at

⇒0 = u + (−9.8 × 3)

⇒ u = 9.8 × 3 = 29.4 m/s

Hence, the ball was thrown upwards with a velocity of 29.4 m/s.

I hope, this will help you.☺

Thank you______❤

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