Question

A ball is thrown up vertically with speed u. At the same instant another ball b is released from rest from height h. After time t

Answer 1

Hey mate !!!!!

Here is your answer....

At time t,

speed of a= 10 – gt

speed of b = 0 – gt

Speed of a relative to b = 10 – gt + gt = 10m/s

Hope it helps..

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Answer 2

Answer:

u

Explanation:

Let us take the point from where the ball A is thrown upwards as origin and the upwards direction positive for ball A. The ball is thrown up with a velocity u at time t =0. It is acted upon by acceleration (-g) due to gravity. The velocity of the body at time t= t is given by

v(A) = u - g t and directed upwards–––––––––(1)

At the same instant of time t=0, another ball is dropped from top of tower. Its initial velocity = 0, and it is acted upon by acceleration (-g) due to gravity.We have taken up as positive. Its velocity after an elapse of time t=t is given by;

v(B) = - g t directed downwards.

To find the velocity of A relative to B, we need to bring B to rest by imposing on B a velocity equal to (+g t). The same velocity also needs to be imposed on A as well. Velocity of B after imposing velocity (+g t) on is zero. And the velocity of A after imposing a velocity (+g t) on it also = u - g t + g t = u

So velocity of A relative to B after a elapse of time t seconds = u and directed upwards, ie relative velocity is always u.

(originally answered by SP Sud )

Hope it helps