a ball is thrown up with 20m/s at an angle 60 with x-axis the velocity of the ball at top position is????
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Answer:
10 m/s
Explanation:
At the topmost position of the ball, the vertical component of the velocity is zero leaving only the horizontal component active for the ball to continue moving forward. The horizontal component of 20 m/s at 60 degrees from the horizontal is vx = 20 m/s * cos of 60 degrees. vx = 20 m/s * 0.5 which gives a product of 10 m/s.
In summary, the velocity of the ball at its topmost position is 10 m/s.
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