a ball is thrown up with a speed of 0.5 m/s.how far it will go before it falls
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H = u^2 / (2g)
= (0.5)^2 / (2 * 10)
= 0.0125 m
It will go 0.0125 m above the ground before it falls.
= (0.5)^2 / (2 * 10)
= 0.0125 m
It will go 0.0125 m above the ground before it falls.
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