a ball is thrown up with a speed of 0.5 m/s.how far it will go before it falls
Answers
Answered by
1
H = u^2 / (2g)
= (0.5)^2 / (2 * 10)
= 0.0125 m
It will go 0.0125 m above the ground before it falls.
= (0.5)^2 / (2 * 10)
= 0.0125 m
It will go 0.0125 m above the ground before it falls.
Similar questions
India Languages,
7 months ago
Math,
7 months ago
English,
1 year ago
English,
1 year ago
Science,
1 year ago