Question

A ball is thrown up with a speed of 15 m/s. How high will it go before it begins to fall (g = 10 m/s2)?
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Answer 1

Answer:

Please note that here the ball is going up against the gravity ,so the value of g is to be taken as negative . Thus the ball will go the a maximum height of 11.4 meters before of begins to fall.

Step-by-step explanation:

Final speed at the top most point (v) = 0

Initial speed (u) = 15 m/s

a = -g = -9.8

Hence, as per the third law of motion,/

v square = u square + 2.a.s

or distance s = (v square - u square)/2.a

or s = (0 - 225)/(2 x -9.8)

or s = 225/19.6 = 11.48 mtrs Answer

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Answer 2

Answer:

gh

Step-by-step explanation: