Physics, asked by boostergaming12, 7 months ago

 A ball is thrown up with a speed of 15 m/s. How high will it go before it begins to fall ? Take g=9.8m/s^2​

Answers

Answered by ShashwatTSS
1

Answer:

h= 11.4 m

Height it will go is 11.4 m

Hope its helpful

Answered by yashsaudarshan
1

Answer:

h=11.47

Explanation:

ball fall in down so it against gravity g is negative

by using second equation of motion

v sq = u sq + 2as

0sq =15sq +2gh (final velocity is 0 and a=g )

0 =225+2*-9.8*h

19.6h=225

h=225/19.6

h=11.47

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