A ball is thrown up with a speed of 15 m/s. How high will it go before it begins to fall ? Take g=9.8m/s^2
Answers
Answered by
1
Answer:
h= 11.4 m
Height it will go is 11.4 m
Hope its helpful
Answered by
1
Answer:
h=11.47
Explanation:
ball fall in down so it against gravity g is negative
by using second equation of motion
v sq = u sq + 2as
0sq =15sq +2gh (final velocity is 0 and a=g )
0 =225+2*-9.8*h
19.6h=225
h=225/19.6
h=11.47
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