A ball is thrown up with a speed of 15 m/s. how high will it go before it begins to fall?
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Explanation:
(v) = 0(u) = 15 m/s
a = -g = -9.8
s= (v)^2 - (u) ^2/2a
s = (0 - 225)/(2 *-9.8)
= 225/19.6
=11.47 m
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