Question

A ball is thrown up with a speed of 5m/s.
How long will it take to reach the ground ?

Answer 1

Answer:

The equation is given as $v^{2} - u^{2} = 2as$

where,

v = final velocity,  

u = initial velocity,  

a = acceleration due to gravity,$10m/s^{2}$

s = h = height traveled.

Therefore, we can find u with above info. In this case, v = 0 at the top of the path.

0−$u^{2}$2×10×5=10m/s.

Hence, the initial velocity of the ball was 10 m/s.