Question

A ball is thrown up with a speed of
L15 m/s. How hight it will go before
it begin to fall ? (g = 9.8 m/s2)
​

Answer 1

Answer:

11.48 m (approx.)

Explanation:

Given:

Initial velocity (u) = 15 m/s

Final velocity (v) = 0 m/s

Deceleration (negative acceleration) = -9.8 m/s²

To find:

Displacement (s)

Method to find:

v² = u² + 2as

⇒ 0 = 15² + (2*-9.8s)

⇒ 0 = 225 - 19.6s

⇒ 19.6 s = 225

⇒ s = 225/19.6 = 11.4795918367 m ≈ 11.48 m

Hence, it will go roughly 11.48 m high before it begins to fall.