A ball is thrown up with a velocity of 10m/s from the top of a tower 495m.find the time taken by to reach the ground?
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Answered by
5
Answer:
u = +10m/s, a = -10m/s² and s= -40m (at the point where stone strikes the ground)
Substituting in s = ut + 1/2at², we have
-40 = 10t - 5t²
or 5t² - 10t - 40 = 0
or t² - 2t - 80
Solving this, we have t = 4s and -2s. Taking the positive value t = 4s.
Explanation:
Hope this helps you unnie ❣️
Answered by
1
Answer:
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Explanation:
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