Question

A ball is thrown up with a velocity of 10m/s. In what time will it
reach the highest point of its journey? Find the highest point of its
journey
​

Answer 1

Answer:

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Explanation:

given that,

A ball is thrown upwards with a velocity of 10m s.

so , here

initial velocity of ball = 10 m/s

since ,

it threw in the upward direction

let the maximum height at which ball will reach be h

so, let at the maximum height final velocity be v,

so,

we have ,

initial velocity (u) = 10 m/s

final velocity (v) = 0

gravitational acceleration (g) = 10 m/s²

1.( by the motion formulae of gravitation

v² = u² + 2gh

now putting the values

(0)² = (10)² + 2(10)h

20h + 10000 = 0

20h = -10000

h = -10000/20

h = -500 m

negation of height shows the height against the gravitational force .

so,

maximum height at which ball will reach = 500 m