A ball is thrown up with a velocity of 15 M per second what is the maximum height attained by it G value is 9.8 M per second square
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u=15m/sec
v=0m/sec(when we throw ball upward then it come down)
g=9.8m/sec square
height (h) =?
according to 3rd equation of motion.
v^2-u^2=2gh
0^2-15^2=2*-9.8*h
0-225=-19.6h
-225/-19.6=h
225/19.6=h
h=11.47m
I HOPE THIS HELPS YOU
v=0m/sec(when we throw ball upward then it come down)
g=9.8m/sec square
height (h) =?
according to 3rd equation of motion.
v^2-u^2=2gh
0^2-15^2=2*-9.8*h
0-225=-19.6h
-225/-19.6=h
225/19.6=h
h=11.47m
I HOPE THIS HELPS YOU
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