Question

a ball is thrown up with a velocity of 20 metre per second if the acceleration is 10 metre per second square in downward direction find the maximum height reached by it​

Answer 1

Answer:

the maximum height reached by the ball thrown upwards with some velocity u is equals to u square by 2g. here g is acceleration due to gravity . therefore 20 square divided by 2(10) girls girls 20 matters therefore the ball reaches to the max height of 20 metres

Answer 2

Answer:

20 m

Explanation:

initial velocity,u=20 m/s

final velocity,v=0m/s (as the ball will be at rest at the maximum height)

a= -10m/s

v=u+at

0=20+(-10)t

=-20=-10t

t=-20/-10

t=2s

s=ut+1/2 at2

s=20*2 + 1/2 (-10)*2*2

=s=40+(-20)

s=20m

therefore, the ball will reach at a maximum height of 20m

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