Question

a ball is thrown up with some velocity after time t second it is at height h from ground which is given by h=at-1/2bt^2 the dh/dt is zero at t equal to​

Answer 1

Answer:

$t = a \div b$

Explanation:

dh/dt=0

d(at-1/2bt^2) /dt = 0

After differentiation

a-bt =0

bt=a

t=a/b