A ball is thrown up with speed of 0.5 m/s How long will it take to reach at that height
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Answer:
Time taken to reach 0 speed (at maximum height) t = (v-u) a = (0 - 0.5) / (-10) = (1 / 20) seconds
Explanation:
Case of uniform acceleration of g along the vertical direction = 10 m/sec^2 downward taking the vertically up direction as positive..
Formula v = u +at is the relevant one having the required quantity and given quantities
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