Question

A ball is thrown up with speed of 10 m/s. How high will it go before it begins to falls?
Take g=10m/s2

Answer 1

Answer:

5 meters

Explanation:

u = 10 m/s

v = 0 m/s

a = -10 m/s^2

Now distance (s) = (v^2 - u^2)/2 a

s = (v^2 - u^2)/2 a

= 0 - 100/  2 x -10  = -100 / -20 = 5 meters

Answer 2

Answer:

5m

Explanation:  

u = 10 m/s

v = 0 m/s

a = -10 m/s^2

Now distance (s) = (v^2 - u^2)/2 a

s = (v^2 - u^2)/2 a

= 0 - 100/  2 x -10  = -100 / -20 = 5 meters