Question

A ball is thrown up with velocity 19.6 m/s. The maximum
height attained by the ball is
(a) 29.2 m (b) 9.8 m
(c) 19.6 m (d) 15.8 m

Answer 1

Answer:

19.6 metres

Explanation:

Given :

• Initial velocity of the ball = u = 19.6 m/s

• Gravitational force = g = 9.8 m/s²

To find :

• The maximum height attained by the ball when thrown up

Maximum height attained = u²/2g

Maximum height attained = 19.6²/2×9.8

Maximum height attained = 19.6×19.6/9.8×2

Maximum height attained = 19.6×19.6/19.6

Maximum height attained = 19.6 metres

The maximum height attained by the ball is equal to 19.6 metres

(c) is correct