Physics, asked by Akki4640, 1 year ago

A ball is thrown upward and it reaches a height of 40m. The velocity with which it was thrown is

Answers

Answered by sreepallavi
0
g=10m/s^2
h=40m
v=0 at the maximum height
using the formula v^2-u^=2gh
u^2=2*10*40
u^2=800
u=√800
u=20√2
20*1.414
28.28m/s


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