Question

A ball is thrown upward and reaches a height of 64 feet it and its initial velocity should be (g=32 feet per second square)​

Answer 1

Hii mate..

your solution ✌✌

Answer 2

v=0

h=64 feet=19.5mts

g=32 feet=9.75mts=9.8mts.

v^2=u^2+2gh

0^2=u^2+2×9.8×19.5

0=u^2+382.2

-382.2=u^2

u=root of -382.2

u=19.54m/s

Hope this helps you n happy friendship day