Question

A ball is thrown upward at 20m/s. Calculate (a) how high it goes (b) the time taken to reach this height (c)the time taken to return to its starting point.(taking acceleration due to gravity as 10m/s2. Please elaborate and explain

Answer 1

Hey
here is your answer
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at maximum height final velocity will be 0
now we know that
v^2-u^2=2as
0^2-20^2=2*-10*s
-400=-20s
s=10m

also
v=u+at
0=20+(-10)t
20=10t
t=2s

also time taken to go upwards=time taken to return back
therefore time taken to return back=2s
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