a ball is thrown upward at the speed of 10m/s from the top of the tower and its reaches the bottom of the tower after 6 seconds what is the height of the tower (g=10m/s2)
Answers
Answered by
0
Explanation:
may be 235 I m not sure
yguj
Answered by
0
Answer:
the height of the tower is 5m metre.
Explanation:
u=0m/s
v=10m/s
g=10m/s^2
t=6s
we know,
v^2=u^2+2gh
100=0+2×10×h
100=20h
5m=height of the tower
Similar questions