A ball is thrown upward from edge of a cliff with
an initial velocity of 6 m/s. How fast is it moving
1/2 s later ? (g = 10 m/s2)
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Answer:
hey buddy hope it helpss..
plzz refer to the attachment ..
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Answer:
THE ANSWER IS 1M/S
Explanation:
GIVEN
u=6m/s
v=?
t=0.5sec(simplified)
now use this equation
V=U-AT
V=1M/S
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