Question

A ball is thrown upward from ground it crosses a point at height of 25m twice at an interval of 4sec

Answer 1

Ok, but Can I ask that we have to find what here?

Answer 2

2sec to reach the highest point where velocity will be zero(0) from the point 25 m above the ground .

V=u-gt

V=20m/s

Again, v^2-u^2=-2gs

V=20,u=?,s=25

u=30m/s

Hope it helps you....

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