Question

a ball is thrown upward from the surface of the moon with a velocity of 19.6 m/s.(a) how much time will it take to attain the maximum height?(b) how high will it go?​

Answer 1

Answer:

V = 0, u = 19.6m/s, g = -9.8m/s²( as ball is thrown upwards)

v = u + at

0 = 19.6 + (-9.8)×t

-19.6 = - 9.8t

t = 20 sec

Therefore, the time taken to attain the maximum height is 20 sec.

2gh = v² - u²

2×-9.8×h = (0)² - (19.6)²

-19.6 = 0 - 19.6 × 19.6

-19.6h = -(19.6×19.6)

h = 19.6 * 19.6 / 19.6

h = 19.6 m

Therefore, the ball will go 19.6 metres high.

Hope it's help you.........

Answer 2

Answer:

(a) the time taken by the ball is 19.6m/s . (b) 1960cm high.

Explanation:

(a) because of the no given maximum time that's why the answer is in the question.