Question

A ball is thrown upward from the surface of the Moon with a velocity of 19.6 metre per second a how much time will it take to attend the maximum might be how high will it go

Answer 1

Hi,

Here is the answer to your question:

u(initial velocity) = 19.6 m/s

at highest point v(final velocity)=0

using v=u+at

0=19.6 - 9.8 * t

t=19.6/9.8= 2s (time to reach max height)

now using v^2 - u^2 = 2as

0 - (19.6)^2 = 2* 9.8 * s

s= 19.6*19.6/2*9.8

s=19.6 m





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