Question

a ball is thrown upward with a certain speed.it passes through the same point after 3 second and 7 second from the start . the maximum height achieved by the ball is​

Answer 1

Answer:

The maximum height achieved by the ball is 125 m

Explanation:

According to the problem the ball is thrown upward.

After 3 second it will reach at the top most position within = 7-3/2 = 2 sec

Therefore the ball will take 3+2 or 5 sec to reach at the top from the bottom.

Therefore for downward direction the motion will be,

u = 0, acceleration, a= g= 10 m/s^2,  t = 5 sec

Let the maximum height is h

hence h = 1/2 x g x t^2 = 1/2 x 10 x 5^2 = 125 m

Answer 2

Explanation:

hope this helps"