Physics, asked by mepayu, 6 months ago

A ball is thrown upward with a speed of 10 m/s . Calculate the speed of the ball after 1 sec ....
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Explain it plzz fast​

Answers

Answered by suvradash
1

Explanation:

Using the equation v = u + at, where ‘v’ is final velocity (what we want to calculate), ‘u’ is the initial velocity (10 m/s in this case), ‘a’ is acceleration (because the ball is being thrown up, acceleration due to gravity will be -9.8 m/s^2), and ‘t’ is the time (in this occasion it’s since the ball was thrown).

So plugging the numbers into the equation:

v = 10 + (-9.8)*(1)

v = 10 - 9.8

v = 0.2 m/s

Answered by asma123rsl
2

Answer:

Explanation:

vf=vi-gt

vi=10m/s

t=1s

vf=10-[9.8]1

vf=0.2m/s

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