Physics, asked by 000parminderkau, 10 months ago

A ball is thrown upward with a speed of 10 metre second -1 calculate the speed of ball after 1 second

Answers

Answered by MDbosskiller0000
45

here is your answer mate:-

using the equation v=u+at

v= final velocity (which should be calculated)

u= initial velocity

(10m/s in this case)

a= acceleration (the ball is thrown up)

so acceleration due to gravity will be -9.8m/s/s.

t= time

now plugging the no. into the equation

v = 10 + (-9.8) * (1)

v = 10 - 9.8

v = 0.2 m/s

there fore the speed of ball after 1 second is 0.2 m/s

hope it helps

plz mark as brainliest

thank you

Answered by rhythmadalakha
2

Answer:

Answer is 0

Explanation:

u=10 m/s

t=1 sec

g=9.8m/s

v=?

v=u+at

v=10+(-10)×1

v=10-10=0m/s

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