A ball is thrown upward with a speed of 20m/s. Fond the time take taken to reach the its top position. In this question if i use v= u +at the answer comes out to be 2sec, but if i use v^2-u^2=2as then the height comes out to be 20m and time comes out to be 1sec. I m very confused in this
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Answer:
the ball will travel for 2 seconds and complete a distance of 20 metres upwards
Step-by-step explanation:
These questions can be answered by making use of Newton's equations of motion. There are 3 equations of motions.
Using First Equation
v=u+at
0=20−10t
10t=20
t=2
Using the Second equation,
v2=u2+2as
02=202+2×(−10)×s
20s=400
s=20
Hence, the ball will travel for 2sec and will complete a distance of 20m
Hope this is helpful.....
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