Question

A ball is thrown upward with a speed of 39.2 metre per second calculate the maximum height it reaches and the time taken in reaching the maximum height

Answer 1

time=4sec
max height=78.4m is the answer

Answer 2

u = 39.2 m/s
v = 0
g = -10 m/s^2
applying v=u+at where t=time
0=39.2-10t
t=3.92sec
now applying s=ut+(at^2)/2. where s=height
s=230.496m