A ball is thrown upward with a speed of 3m per second from the tower 50m high.find the speed with which it striles the ground.
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We will use the following kinematic equation :
V² = u² + 2gs
g = 9.8 m/s²
let S1 be displacement upwards.
From the formula we can get S1:
u = 3 m/s
v= 0
g = 9.8 m/s²
0 = 9 - 2 × 9.8 × S1
S1 = 9 / 19.6 = 0.46 M
total displacement :
50 + 0.46 = 50.45 m
Now we want v :
u = 0 for a freely falling body hence.
V² = 0 + 2 × 9.8 × 50.46
v² = 989.02
v = 31.44 m/s
V² = u² + 2gs
g = 9.8 m/s²
let S1 be displacement upwards.
From the formula we can get S1:
u = 3 m/s
v= 0
g = 9.8 m/s²
0 = 9 - 2 × 9.8 × S1
S1 = 9 / 19.6 = 0.46 M
total displacement :
50 + 0.46 = 50.45 m
Now we want v :
u = 0 for a freely falling body hence.
V² = 0 + 2 × 9.8 × 50.46
v² = 989.02
v = 31.44 m/s
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2
Answer:
v= 31.44m/s
Explanation:
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