Question

A ball is thrown upward with a velocity of 10 m/s. calculate the speed of the ball after 1 seconds.Take g=9.8​

Answer 1

Answer:

0.2 m / sec

Explanation:

Given :

Initial velocity ( u ) = 10 m / sec

Time ( t ) = 1 sec

Acceleration ( g )  = 9.8 m / sec²

Now ,

We have :

v = u +  g t

v = 10 + ( - 9.8 × 1 )    [ ball thrown upward g against earth hence we took g as negative ]

v = 10 - 9.8

v = 0.2 m / sec

Hence we get answer .

Answer 2

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Speed of the ball thrown upward after 1 second will be 0.2 m/s

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Given :

• A ball is thrown therefore it will have initial velocity (v) = 10m/s
• Time = 1 second
• Acceleration due to gravity (g) = 9.8 m/s²

To find :

• Speed of the ball after 1 second (v)

Solution :

We have in the question the following quantities :

Initial Velocity, Time, Acceleration (due to gravity)

Therefore, we can use the first equation of motion.

$\bold{v\:=\:u\:+\:a\:t}$

But since here in this question, we have been provided by the value of g (gravitational acceleration) so instead of a in the equation, we will use g.

$\implies$ $\bold{v\:=\:u\:+\:g\:t}$

$\implies$ $\bold{v\:=\:10\:+\:(-9.8)\:(1)}$

[Since the ball is thrown upward against the gravity, the value of g will be negative.]

$\implies$ $\bold{v\:=\:10\:\:-9.8}$

$\implies$ $\bold{v\:=\:0.2}$

•°• v =0.2 m/s