Question

A ball is thrown upward with a velocity of 10 metre per second find the maximum height reached by the ball and the time taken to come back to the thrower (g=10m/s^2

Answer 1

Step-by-step explanation:

h = -u^2/g

h= -100/-10 = 10 m

t = v-u/g

t = 10/10 = 1 second

total time = 2 second

Answer 2

Answer:s= 5m t=2s

v=u+at

10=0+10×t

t=1s

But as the ball goes upward as well as downward

t= 1×2

t=2s

v2=u2+2as

100=0+2×10×s

100=20×s

100/20=s=5m/s^2

Step-by-step explanation: