A ball is thrown upward with a velocity of 100 m s it will reach the ground after
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Answered by
6
velocity=100m/s(initial)
final velocity =0
v^2-u^2=2(-g)×s
0-100×100=-2×10×s
s=500m
time taken from going bottom to top
=500/100=5sec
time for overall journey=5sec(going up)+5sec(coming down)=10sec.
so answer is 10 sec.
hope this will help you.
final velocity =0
v^2-u^2=2(-g)×s
0-100×100=-2×10×s
s=500m
time taken from going bottom to top
=500/100=5sec
time for overall journey=5sec(going up)+5sec(coming down)=10sec.
so answer is 10 sec.
hope this will help you.
Answered by
4
short n easy go to formula V=at
here v=100 a is due to gravity that 10 n t=?
whereas 100=10×t
100/10=t
t=10
here v=100 a is due to gravity that 10 n t=?
whereas 100=10×t
100/10=t
t=10
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