Question

a ball is thrown upward with a velocity of 19.6m per second it will come back to ground after how many seconds​

Answer 1

Initial velocity is:. 19.6m/s

Final velocity is:. 0m/s

Acceleration is :. -9.8m/s^2 【due to force of gravity towards down】

Time:. ?

By first equation of motion

v = u+at

0 = 19.6+(-9.8)t

-19.6 = -9.8t

therefore time is

-19.6/-9.8

That will be ,

2 seconds

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Answer 2

Answer:

a=-9.8

v=0

u=19.6

t=?

v=u+at

0=19.6+(-9.8)*t

-19.6=-9.8*t

t=19.6/9.8

t=2sec