A ball is thrown upward with a velocity of 19.6m/s.Calculate time of ascent, time of descent and time or flight
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Thus ,the intial velocity of the ball is 19.6 m/s which means that the ball has been thrown upwards with a velocity of 19.6 m/s . Thus the ball takes 2 seconds to reach the highest point of the ground . In other words ,the ball will take a total of 2+2=4 second to reach back to the thrower.
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