A ball is thrown upward with a velocity of 40 m/s from top of a tower having a height of 45m. What time
elapsed when it again passes the edge of tower ( g =10ms-2)
(a)2s (b) 4s (c) 8 s (d) 5s
note :steps are needed
Answers
Answered by
1
Answer:
U should use this formula
Speed =distance /time
Hope its help you
Answered by
0
use formula s=ut+1/2at^2
Similar questions